4x^2=50,2*(0,01-0,2x+x^2)

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Solution for 4x^2=50,2*(0,01-0,2x+x^2) equation: 



4x^2=50.2(0.01-0.2x+x^2)

We move all terms to the left:

4x^2-(50.2(0.01-0.2x+x^2))=0



We calculate terms in parentheses: -(50.2(0.01-0.2x+x^2)), so:

50.2(0.01-0.2x+x^2)

We multiply parentheses

50.2x^2+0x+0.502

We add all the numbers together, and all the variables

50.2x^2+x+0.502

Back to the equation:

-(50.2x^2+x+0.502)



We get rid of parentheses

4x^2-50.2x^2-x-0.502=0

We add all the numbers together, and all the variables

-46.2x^2-1x-0.502=0

a = -46.2; b = -1; c = -0.502;
Δ = b2-4ac
Δ = -12-4·(-46.2)·(-0.502)
Δ = -91.7696
Delta is less than zero, so there is no solution for the equation

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